跳字鐘計算題

一天小明在火車站等候火車﹐望著牆上跳字鐘顯示 03﹕33。他無聊地想﹐
究竟一個12小時跳字鐘在一天內會有多少次同時出現三個或以上連續相
同數字顯示在跳字鐘上呢﹖


[wow]回覆可見ans[/wow]

0000 0001 0002 0003 0004 0005 0006 0007 0008 0009 0111 0222 0333 0444 0555 1111 1110 1222 1000 x2 -1係咁多,唔知仲有冇呢??
37

I think your answer have something wrong, a 12-hours 跳字鐘 will display 00:00 when mid-night, not 12:00. so the answer is:

AM
0000, 0001, 0002, 0003, 0004, 0005, 0006, 0007, 0008, 0009 ->10
0111, 0222, 0333, 0444, 0555 -> 5
1000 -> 1
1110, 1111, 1112, 1113, 1114, 1115, 1116, 1117, 1118, 1119 -> 10

PM
1222 -> 1
0111, 0222, 0333, 0444, 0555 -> 5
1000 -> 1
1110, 1111, 1112, 1113, 1114, 1115, 1116, 1117, 1118, 1119 -> 10

Answer is 43